$y^2+y^2$
$\frac{d}{dx}\left(3x^2+1=4x+b\right)$
$\frac{x^5-x^4+x^2-2}{x^2+6}$
$\int\frac{1}{x\sqrt{x-4}}dx$
$\:\frac{x^6+64}{x+2}$
$\left(-3\cdot x^3-2\cdot x^2\right)^3$
$x+9=16$
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