$sec\:a\:-\:cos\:a$
$\left(x+y\right)dx=\left(x+y-4\right)dy$
$\left(a+b\right)\left(a^4+a^2b^2-b^4\right)$
$\frac{x^2+2}{x^2-4}=\frac{x}{x-2}$
$3\left(3\right)-4\left(-2\right)$
$\frac{\left(x^3-6x^2+9x-1\right)}{x-1}$
$\left(13+m\right)\left(13-m\right)$
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