$-243^{\frac{1}{5}}$
$\lim_{x\to0}\left(\frac{7^x-5^x}{4^x-3^x}\right)$
$\frac{\left(-150\right)}{150}$
$\left(5u-3v+3a^2\right)^2$
$\lim_{x\to90}\left(\frac{2cos\:^2\:x+cosx-1}{2cos^2-3cos+1}\right)$
$4x^2-3x-1;\:x=-3$
$75+12+32\:18$
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