$\left(2a+3b^2\right)\left(2a-3b^2\right)$
$10\:x\:-\:4\:.\left(\:x\:+\:1\right)\:\ge\:13\:+\:3\:x\:$
$\int\frac{6}{\left(x+x^2\right)^3}dx$
$\frac{2}{3}^{-0.5}$
$\lim_{x\to-19}\left(\frac{x^2-361}{x-19}\right)$
$\int\:\left(4w\:-\:1\right)^3\:dw$
$8^{3^2}$
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