(5−42)+8\left(5-4^2\right)+8(5−42)+8
∫e−x(1+e−x)2dx\int\frac{e^{-x}}{\left(1+e^{-x}\right)^2}dx∫(1+e−x)2e−xdx
4x2+10xy+10x+25y4x^2+10xy+10x+25y4x2+10xy+10x+25y
∫x(x2−2x+3)dx\int x\left(x^2-2x+3\right)dx∫x(x2−2x+3)dx
limx→0e4x−1−4xx2\lim_{x\to0}\frac{e^{4x}-1-4x}{x^2}x→0limx2e4x−1−4x
−(−7)⋅(−5)⋅(−3)⋅(−2)-\left(-7\right)\cdot\left(-5\right)\cdot\left(-3\right)\cdot\left(-2\right)−(−7)⋅(−5)⋅(−3)⋅(−2)
dydx(x−1)2+(y−1)2=13\frac{dy}{dx}\left(x-1\right)^2+\left(y-1\right)^2=13dxdy(x−1)2+(y−1)2=13
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