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$4\frac{x^3-3x^2+2x+4}{x-7}$
$2x^2+\frac{2}{x}+1$
$3\:+\:4\:.\:\left(8\:.\:\left(4-\left(9\:+\:3\right)\::\:6\:\right)\right)$
$-n+1\left(-4\right)-\left(-4n\right)+6$
$\left(2x^2+9\right)\left(2x^2+5\right)$
$\lim_{x\to\infty}\left(\frac{2x^2+3}{x^2}\right)$
$\log\left(y^3\right)=12$
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