$-35=x-21$
$x^2+9\le0$
$\lim_{x\to0}\:\frac{12x^3}{e^{5x}}$
$1^1+2^2+3^3$
$-20^2$
$\frac{-234}{-13}$
$\lim_{x\to0}\left(9xe^{\frac{1}{x}}-9x\right)$
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