$\int\frac{9}{\left(x+1\right)^2}dx$
$\left(x^2-5\right)^3$
$\frac{x^2+2x-8}{x+8}$
$\sqrt{\frac{1}{4}}t^2u^6$
$\left(h^3\right)^7$
$tan\left(\theta\right)=6$
$\frac{6t-15}{3t-2}$
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