$\frac{d^2}{dx^2}\left(x^2\left(3x-4\right)^3\right)$

$\left(6x^2-3x^5\right)$

$\frac{1}{2}\left[6\ln\left(x+7\right)+\ln\left(x\right)-\ln\left(x^6-5\right)\right]$

$\int\sec^3\left(x\right)+\tan^3\left(x\right)dx$

$+126+452$

$2y^2=100$

$-\left(-4+12\right)-\left(4-11-23\right)$