$\left(x\:+\:6y\:-5z\right)^2$
$12+3y-8-7y$
$-7\:+8\::\:4+3\:x\:2-5$
$\left(5x+2\right)\left(3x\right)$
$\left(\frac{5}{7}x^3y^2+\frac{1}{2}x^2y^3\right)^2$
$\frac{\sin\left(x\right)\sin\left(y\right)}{\cos\left(x\right)\cos\left(y\right)}$
$\left(5a+a^3+a^3\right)$
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