$\frac{x^3}{x-3}$
$\left(\frac{1}{3}b^3a\right)^3$
$4x\:-\:5>6$
$\frac{1}{\left(x+14\right)}+\frac{2}{\left(2x+4\right)}+\frac{5}{\left(2x+1\right)}$
$-2m^3n\left(-10m+5mn-y\right)$
$\left(b+5\right)\left(b+3\right)$
$-3435+2570$
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