$\lim_{x\to3}\left(\frac{\sqrt{x}^2-9}{x-3}\right)$
$3x+1=x+1$
$\frac{2x^7-4x^6+2x+3}{x-2}$
$\lim_{x\to a}\left(\frac{x^2-\left(a+1\right)x+a}{x-a}\right)$
$\left(3u+u^4v^2\right)^3$
$3\left(3\right)^3+1$
$\left(x^3y\frac{dy}{dx}=y^2x^6\right)$
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