$\lim_{x\to0}\frac{4x+3}{8x-3}$
$0.3\left(x+4\right)+1.3\left(x-3\right)$
$\int\left(\frac{6x-1}{2x^4-x^3}\right)dx$
$\lim_{x\to-\infty}\left(\frac{x+1}{x^2-4}\right)$
$-8\:-7-3\:-1\:+1\:+2+\:+5\:$
$\left(6m^5+4n^6\right)^2$
$\log_w\left(625\right)=4$
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