$\left(a^3+8\right)\left(a^3+3\right)$
$\left(\frac{1}{\sin^2\left(x\right)}-\frac{1}{x^2}\right)$
$\lim_{x\to4}\left(2x^2-7x-4\right)$
$a^2x-4a^2x^2+5ax^3-x^4\:\:\left(\:2x\right)\:\:$
$\left(x-\frac{y}{2}\right)^{\frac{1}{2}}$
$3.77\cdot0.375$
$7+\sin^{2}\theta$
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