$\:\frac{1}{5-x}\frac{1}{-\left(5-x\right)}$
$\lim_{x\to1}\left(\frac{ln\:x}{6x-x^2-5}\right)$
$4x^2-12x+9=9$
$10=3+s$
$y=\sqrt[3]{x}\left(x^4+1\right)^{12}e^{2x^2+1}$
$5x+2\left(x+1\right)\ge23$
$x^2-6x+12>3$
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