$9x^2+9y^2+12x+36y-104=0$

$\lim_{x\to\infty}\left(\frac{\tan\left(\frac{1}{x}\right)^2}{\ln\left(1+\frac{4}{x}\right)^2}\right)$

$9\cdot32$

$3x\left(2x-1\right)^2-2\left(x-3\right)\left(x+3\right)$

$\left(-x^4+3x^3+7x^2+16x-5\right):\left(x-5\right)$

$\int\frac{3.1\sin\left(10x\right)}{5+\cos\left(10x\right)}dx$

$+\frac{3}{4}xy^2+\frac{1}{8}xy^2$