$m=\left(x+8\right)\left(x+9\right)$
$16x^2+12+36$
$\frac{dy}{dx}+\frac{1}{x}\left(y\right)=\frac{1}{x^2}$
$10x^3-24x^2-18x$
$\frac{x^3}{x^2-4x+4}$
$\left(x^2-5x\right)-\left(-x^2+6\right)$
$\left(2x-7\right)\frac{1}{2}$
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