(xyz+2)3\left(xyz+2\right)^3(xyz+2)3
x+12=126x+12=126x+12=126
∣(−5)⋅(−2)⋅(−3)∣2\left|\left(-5\right)\cdot\left(-2\right)\cdot\left(-3\right)\right|^2∣(−5)⋅(−2)⋅(−3)∣2
xy′−5y=0xy'-5y=0xy′−5y=0
y′=xy−3y+x−3xy+2y−x−2y'=\frac{xy-3y+x-3}{xy+2y-x-2}y′=xy+2y−x−2xy−3y+x−3
x−2y−3z=−1x-2y-3z=-1x−2y−3z=−1
(2x+5)(2x−9)\left(2x+5\right)\left(2x-9\right)(2x+5)(2x−9)
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