$\frac{dy}{dx}=\frac{\left(5\right)}{\left(x^2\right)}$
$10^3.10^6$
$\int\frac{\left(x+4\right)^5}{u}dx$
$\left(3^5\cdot5^{-4}\right)\left(2^3\cdot3^7\cdot5^6\right)$
$\left(11m^3-3m^2\right)^2$
$\left(3\sqrt{x}\right)^3$
$\left(2b+4\right)\left(2b-10\right)$
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