$$\lim_{x\to1}\left(3x^2-4x+1\right)$$

$$\sqrt{244}$$

$$4x^{2}-5x-2=0$$

$$\lim_{n\to\infty}\:\frac{8^n}{2^n+1}$$

$$x^2-5x+12=0$$

$$sin^2x-cos^2x=1-2sin^2x$$

$$\lim_{x\to\infty}\:\frac{3x}{\sqrt{\left(x\right)^3\:+\:2}}$$