$\frac{2x^2-6x+4}{x-5}$
$10x^2-x-4=0$
$\frac{9}{11}+\frac{-4}{11}+\frac{-5}{11}$
$\lim_{x\to h}\left(\frac{y+h}{h^2-y^2}\right)$
$-28+4$
$in\left(x^5\left(3x+7\right)^9\right)$
$\int14\cdot sec\:^3\left(x\right)dx$
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