$y'+3y=x+e^{\left(-2x\right)}$
$\frac{4b^3-5b^2+3b-2}{b-2}$
$\frac{1}{\left(y^2+1\right)}\cdot dy-\frac{x}{\left(x+1\right)}\cdot dx=0$
$\frac{8x^2+36x-72}{2x-3}$
$\sqrt[5]{n^4+3-12}$
$\frac{dy}{dx}=\tan\left(4\cdot x\right)$
$x^2-3x+1.5$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!