$\sqrt[3]{8}-3$
$sin^4y-cos^4y=2\:sin^2y-1$
$\left(\frac{\frac{-6x^3}{5}}{\frac{-2x}{5}}\right)$
$\left|4-16-\left(0\right)\right|$
$8+3\left(16-12\right)$
$\frac{dy}{dx}=4x+5y-9$
$\frac{dy}{dx}=\frac{y}{x\log\left(x\right)}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!