$\lim_{x\to3}\left(\frac{x^3-12}{x-3}\right)$
$10\left(-4\right)+18$
$1-\tan^2m$
$-4x^3+x^3+x^3-6y^3+y^3+4y^3-3$
$9^x-3\left(3^x+1\right)$
$buym0zuy$
$\left(x^3+\:7\right)\left(x^3\:-\:6\right)$
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