$\int\frac{x}{\left(x+1\right)^2-6}dx$
$2x^2+12x-5=0$
$\:\frac{x^4+6x^3-24x+16}{x+4}$
$\int\left(\frac{x^2-2}{x^2\left(x-1\right)}\right)dx$
$\left(x-5\left(x+5\right)\right)$
$4\left(x+3\right)=x+26+2x+x$
$\left(m-2\right)\left(m-3\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!