$\lim_{x\to0}\left(\frac{25}{x^2}\right)$
$\frac{dx}{dv}=\frac{2}{x}$
$12x^2-560x+4800$
$x^2-4x-\frac{4}{x-2}$
$2\:0+1+7$
$\frac{dy}{dx}+7y=7$
$1+\left(-20\right)-\left(-7\right)$
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