ddx(3x)−4x\frac{d}{dx}\left(3^x\right)-4^xdxd(3x)−4x
y=x33−x2−3x+5y=\frac{x^3}{3}-x^2-3x+5y=3x3−x2−3x+5
limx→0(sin(8x)x2)2\lim_{x\to0}\left(\frac{sin\left(8x\right)}{x^2}\right)^2x→0lim(x2sin(8x))2
2sin(20)=−1\sqrt{2}\sin\left(20\right)=-12sin(20)=−1
(2a)12\left(\frac{2}{a}\right)^{12}(a2)12
t2dxdt=1xt^2\frac{dx}{dt}=\frac{1}{x}t2dtdx=x1
∫2x2+3(x2+2)2dx\int\frac{2x^2+3}{\left(x^2+2\right)^2}dx∫(x2+2)22x2+3dx
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