$2xy-4ac+5yx+4ac$
$\sin\left(4\pi x\right)=0$
$y'+3xy^3=0$
$\frac{\infty^4}{\infty^4}$
$\int\left(\frac{1}{\left(4x^2-16\right)^{\frac{3}{2}}}\right)dx$
$\frac{dy}{dx}=kqe^{-kx}$
$\tan\left(g\right)=0.125$
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