$1x^3-x^3$
$\frac{dy}{dx}+3y-3=2x$
$-2\left(-1\right)^2-\left(-2\right)\left(-1\right)^3$
$\left(-6\right)^3-3\left(-6\right)^2-4\left(-6\right)-30$
$9\cdot\sqrt{18}$
$3x+2y=24$
$-14-\left[-6+\left(-15\right)\right]$
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