$x^2+4x\:<\:20$
$\left(2x+\sqrt{3}\right)^2$
$\left(5xy^3+3x^2\right)^2$
$\left(3a^{-1}b^{-3}\right)\left(2a^3b\right)$
$5.3+5.8+6.3+5.0+6.0$
$4tx\frac{dy}{dt}=x^2+1$
$\left(x^6y^{-2}z^{-4}\right)\left(-4yz^{-3}\right)\left(4xy^{-3}z^6\right)$
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