$x+6<4-3x$
$( x ^ { 2 } - y ^ { 2 } ) ^ { 5 }$
$560-\left(-340\right)+90$
$3\left(2-5\right)+\left(3-1\right)$
$12x^2-72x+y+78=0$
$\frac{\left[\left(2-1\cdot3\right)^2+\left(5-4\right)-\left(2\cdot3\right)^4\cdot\left(2\right)^3\right]}{\left(5-3\right)}$
$\tan^2\left(\infty\right)\cdot\left(1-\sin^2\left(\infty\right)\right)=\sin^2\left(\infty\right)$
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