$5.36\cdot\left(-7\right)$
$-1+6\left(0-6\right)$
$\frac{\left(sin^2x-tanx+cos^2x+tanx\right)}{sin^2x}$
$x'\left(t\right)+x=\left(t+1\right)^2$
$36ab+60b$
$\left(4a^2-5m\right)^2$
$ln\:\left(y\right)=4ln\left(x\right)$
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