$\left(-2x-10\right)^2$
$\frac{2}{3}x^8x\left(-\frac{3}{4}x^3-\frac{1}{8}x^2-\frac{1}{6}\right)$
$\left(11x+1\right)^2$
$7x-11\le4x$
$-7x-8\ge-9+9x$
$\frac{x}{x-3}+\frac{2}{x^2+4x+3}$
$\sqrt[3]{\left(27x^2y^{12}\right)}^2$
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