$xy^2=0$
$2x+9>3x$
$2^{-3}+2^2$
$x+3\left(4x^4-40x^2-5x+25\right)$
$-\left(-4\right)-\frac{\left(-16\right)}{2}$
$\left(10d-h\right)^2$
$\int\sin^3\left(1-2x\right)dx$
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