$2\left(2x^5\right)\left(3\right)$
$\lim_{x\to5}\left(\frac{12x-80}{x^2-6x+5}\right)$
$16x\:+\:7y\:+\:3\left(6x\:-\:3\:+\:2y\right)$
$\left(x-4\right)^2>x\left(x+12\right)$
$20x^2-10x+1$
$2x^4-3x^2-2;\:x=2$
$\frac{x+5}{2x+6}>\frac{3}{2}$
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