$48a^4-27b^2$
$\int\frac{6x^3}{x^4+8x^2+16}dx$
$\frac{d}{dx}t\sqrt{10}$
$-\left(3-9\left(1-3+\left(8+2-1\right)-\left(2-5\right)-13\right)+4-3\right)$
$4x+8=12$
$\lim_{x\to0}\left(1+7x\right)^{3x}$
$2x\frac{1}{3}-3x\frac{1}{2}$
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