$\left(c^7\right)^4$
$\int2x^3\left(3x^4+2\right)^4dx$
$\left(-22\right)\cdot\left(-4\right)$
$\frac{2}{x+1}=\frac{4}{x}$
$\frac{d}{dx}\left(y^2=0\right)$
$\left(4a-7\right)\left(4a+3\right)$
$4x^2y^2z^2\:-\:a^2b^2$
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