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$sin^2x=3sinxcosx$
$x^2\:+\:8y^2\:+\:5z^2\:=\:7\:$
$\sqrt[5]{\frac{5x^4y^2}{8}}$
$\frac{x^3-9^3}{x-9}$
$\frac{4x^3-3x^2+1}{6x^2+4}$
$9y^2-1y+1$
$\lim_{x\to0}\left(\frac{\sqrt[3]{8+x^3}-\sqrt{x^2+4}}{x^2}\right)$
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