$\left(3x^2-7x+6\right)\cdot\left(-5x^2+3x-4\right)$
$\int\tan3x\:dx$
$\frac{\left(3x^4-5x^3+2x^2-7x+11\right)}{x+2}$
$-\:\left(-5+6-3+6\right)+3-\left(+5-2+1\right)$
$4a^2-16$
$4\frac{1}{2}+\sqrt{4^2+3^2}$
$\int x.\frac{2x}{x^2}dx$
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