$-t\left(-4t^3+8t^2\right)$
$1-\int\sec^{2}\left(1-4x\right)dx$
$3ax^3-3ay^3$
$\lim_{x\to3}\left(\frac{\left(x^3+27\right)\left(2x+1\right)}{x-3}\right)$
$25m^4+30m^2+9$
$\:\left(x^3+\:xy^2\right)\:dx\:+\:\left(x^2y\:+\:y^3\right)\:dy\:=\:0$
$\int e^{x^5}dx$
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