$f\left(x\right)=x^3-4x^2$
$\frac{dy}{dx}=-\frac{4y^3}{3x}$
$\left(3a\:-\:2b\:+\:7c\right)+\:\left(-4b\:+\:3c\:+2b\right)$
$6^2+18x^3$
$\frac{12x^2-6x+2}{3}$
$\lim_{x\to1}\left(\frac{1-x^2}{\sqrt{3+x}-2}\right)$
$\frac{10x^3-15x^2+20x}{2x^2-3x+4}$
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