$sec\left(x+2\pi\right)\cdot sin\left(x+2\pi\right)$
$\sqrt{2475\:n^5}y^4$
$\tan\left(x\right)=-2019$
$\frac{1}{32}\int_{\frac{-1}{2}}^0\left(\frac{4u^2}{\left(-u^2+1\right)}\right)dx$
$\frac{d}{dx}x^2\:tan\:y=50$
$x+10+9$
$81t^2+72+16$
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