$\frac{\left(-15\right)}{\left(-3\right)}\cdot\left(-9\right)$
$\int\frac{\left(3x^2+5x+8\right)}{\left(x\left(x^2+4\right)\right)}dx$
$x^4+5x^2+4:x-2$
$-8=\:-5+3u$
$121x^4-4y^2$
$x+2y-12x-13y-2x+y-a$
$12c^3-9c^2$
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