$\frac{x^2-6x+12}{x-4}$
$\int x\left(3x^2+3\right)^2dx$
$\frac{\left(3m+2n\right)^2+\left(3m-2n\right)^2}{9m^2+4n^2}$
$x2+5x=-6$
$2\left(x+5\right)^2-\left(x^2-25\right)$
$\frac{\left(\left(a^4\right)\left(x^2\right)\right)}{ax^2}$
$-18+1$
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