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(2cosx−2secx)(cos2x+sec2x+1)\left(2cosx-2secx\right)\left(cos^2x+sec^2x+1\right)

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Final answer to the exercise

2cos⁡(x)3+2sec⁡(x)2cos⁡(x)+2cos⁡(x)−2cos⁡(x)2sec⁡(x)−2sec⁡(x)3−2sec⁡(x)2\cos\left(x\right)^{3}+2\sec\left(x\right)^2\cos\left(x\right)+2\cos\left(x\right)-2\cos\left(x\right)^2\sec\left(x\right)-2\sec\left(x\right)^{3}-2\sec\left(x\right)

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(2cosx−2secx)(cos2x+sec2x+1)
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