$m^2=\frac{36}{25}$
$m^4n^6-y^2$
$5\left(x^2+3y\right)-2\left(4y-x^2\right)$
$0=e^{-x^2}$
$-13+54\::3$
$\sin\left(\frac{x}{3}\right)=\frac{1}{2}$
$\frac{dy}{dx}\left(sen\left(2x-y\right)-cos\left(2y-x\right)+x+y=0\right)$
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