$\int\left(6x^{-3}\right)dx$
$\left(4y^2\right)\left(6y^2-3y+5\right)$
$x^2+10x=336$
$2\sqrt{27x^2}y^5$
$\arccos\left(cos\frac{\pi}{9}\right)$
$\frac{x^2-y^2}{x+y}\cdot\frac{4x+xy}{x}$
$\frac{\left(-2.001\right)^2+\left(-2.001\right)-2}{\left(-2.001\right)+2}$
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