$$-5a^2\:entre\:-7$$

$$\frac{dy}{dx}\:+\:6y=\frac{3}{4}$$

$$x^2-64u^2$$

$$\int\sqrt{4+y}\cdot\left(y+1\right)^{2}dy$$

$$\frac{1+3\cos\left(y\right)}{1+\cos\left(y\right)}=\frac{1+2\cos\left(y\right)-3\cos\left(y\right)^2}{\sin\left(y\right)^2}$$

$$9^5\cdot\:4^5$$