$3x^2+x+-1+5x+x^2+-6$
$x^2+8x=\:33$
$x^5\left(\frac{e}{x^4}\right)$
$\lim_{x\to\infty}\left(\frac{13\left(5^x\right)+12}{8\left(4^x\right)}\right)$
$y=-\frac{4}{3}\left(x-\frac{7}{2}\right)^2+3$
$x^2-12x=45$
$8+4\cdot\left(5-2\right)$
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