$x^2-x+5=0$
$7x^2-5x^3+4x+3-5x^2-2x$
$\left(3x^4y\right)\left(5x^3y^5\right)$
$\int\frac{20x-11}{\left(3x+2\right)\left(x^2-4x+5\right)}dx$
$\frac{x^5+x^2-3}{x^2-x+1}$
$\int\frac{\sec^4\left(4y\right)}{\tan\left(4y\right)}dy$
$2x^2+3x-6$
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